String/Char data types

[sanasuke15]

Hello, I'm trying to write a program that will a overload a function named as the function in the code. So, if the user enters characters like 5 '%' then the program will output 5 other character like '*'. But I've got an error.

If the user will type 10
**********

It will also return a 10 different character

none of the 2 overloads could convert all the argument types
How should I fix this. Also, any help with my code and see what's wrong with it is greatly appreciated

#include <iostream>
#include <cstring>
#include <cctype>
#include <cstdlib>

using namespace std;

void linechar(char);
int linechar (int);

int main()
{
	char str[100];
	cout << "Please enter characters: ";
	cin.getline(str, 100);
	linechar(str); 
}

int linechar(char x[100])
{
	int length=strlen(x);
	int k=linechar(length);
	return k;
}
int linechar (int x)
{
	for (int i=1; i<=x; i++)
	{
		cout << "@";
	}
}

[abhishekm71]

Your function prototype (for char) and definition do not match.

[sanasuke15]

I'm still having the same problem

#include <iostream>
#include <cstring>
#include <cctype>
#include <cstdlib>

using namespace std;

char linechar(char);
int linechar (int);

int main()
{
	char str[100];
	cout << "Please enter characters: ";
	cin.getline(str, 100);
	linechar(str); 
}

char linechar(char x[100])
{
	int length=strlen(x);
	int k=linechar(length);
	return k;
}
int linechar (int x)
{
	for (int i=1; i<=x; i++)
	{
		cout << "@";
	}
}

[abhishekm71]

The prototype still does not match. Try this.

#include <iostream>
#include <cstring>
#include <cctype>
#include <cstdlib>

using namespace std;

int linechar(char []);
int linechar (int);

int main()
{
	char str[100];
	cout << "Please enter characters: ";
	cin.getline(str, 100);
	linechar(str); 
}

int linechar(char x[])
{
	int length=strlen(x);
	int k=linechar(length);
	return k;
}
int linechar (int x)
{
	for (int i=1; i<=x; i++)
	{
		cout << "@";
	}
}

[sanasuke15]

Thank you!! Last question though, can i use srand() to generate random characters because I would to replace cout << "@"; with that. Or is there another function for it. I can't find anything on the internet.

[abhishekm71]

You will need to seed the random generator through srand() once. It usually done through current time.

srand( time( NULL ) );

After that you can call the rand() function (any number of times) that will generate a random number between 0 and RAND_MAX.

Note: The above is the C way of doing it.

The C++ way is to use the <random> header. You can go through its documentation on this website. Just type in random on the search bar on top and it will get you the docs.