trouble with returning a function

[cirwin2010]

I am trying writing a program that will output all prime numbers less than or equal to the entered value. The math in the prime function is correct, but I cannot figure out how to return the output of 'cout << i << " ";'. How can I fix this?

#include <iostream>
using namespace std;

int prime(int n);
int divisible(int n, int d);


int main()
{
int n;
cout << "Please enter a positive integer.\n";
cin >> n;
prime(n);
system("pause");
return 0;
}

int prime(int n)
{
for (int i = 2; i < n; i++){
for (int d = 2; d < i; d++){
if (n % d == 0){
break;
}
else if (i % d != 0){
cout << i << " ";
break;
}
}
}
return;
}

[vasilenko93]

Your return function does not return anything.
return;
Try returning something or a variable.
return n;

[giblit]

well to return cout you will have to return an ostream not an int. Though I don't know why you are. Also to return you put return something; Can you explain what exactly you are trying to return from the function? An array of prime numbers? Then you'd have to return an int * ( int [] ) or a STL container such as a vector or array.