How to equal using assignment operators

[Sharan123]

it shows insertion operators error but works when i use string

  #include<stdexcept>
#include<conio.h>
#include <iostream>
using namespace std;
class vector
{

	
public:
	int x ,y;
	vector(){};
	vector(int a ,int b)
	{
		x=a;
		y=b;
	}
		//: x(a),y(b){}
	vector vector::operator= (vector b1)
	{
		vector b2;
		b2.x=b1.x;
		b2.y=b2.y;
		return (b2);
	}
};
int main () 
{
	vector b1 (3,1) , b2(1,3);
	vector b3;
	b2= b1;
	cout<<b2;
}
 

[mobotus]

cout << b2.x << " " << b2.y;

[Chervil]

I think this is right, though I may have overlooked something:

#include <conio.h>
#include <iostream>

using namespace std;
class vector
{

public:
    int x ,y;
    vector(){};
    vector(int a ,int b)
    {
        x=a;
        y=b;
    }

    vector & operator=(const vector & b1)
    {
        x = b1.x;
        y = b1.y;
        return *this;
    }

    friend ostream & operator<<(ostream & os, const vector & v);
};

ostream & operator<<(ostream & os, const vector & v)
{
    os << '(' << v.x << ',' << v.y << ')';
    return os;
}

int main ()
{
    vector b1 (3,1) , b2(1,3);
    vector b3;
    b3 = b2;
    b2 = b1;
    cout << b2 << " ";
    cout << b3;
}

[Sharan123]

Thank you everythings clear good programming can't we do that without using operator overload for<<

[Chervil]

can't we do that without using operator overload for<<

Of course we can. I gave you that as a free gift, take it if it's useful, ignore it if it isn't.