keep loops asking

[toast9]

how do you make a loop ask for another number after it runs through and does its math with the first number you give it? The code runs perfectly but I want it so I can put a new number in it for it to run through again without having to exit the program.

   int num;
   int answer = 1;

   cout << "Enter a Number: " << endl;
   cin >> num;

  for (int multi = 1; num >= multi; multi++){
      
      answer = answer * multi;
      cout << answer << endl;
   }

[Danny Toledo]

Put the code (lines 2-12 inclusive) inside of a do while loop and make it exit when num is something like 0 or -1 (you will also want to change the prompt to reflect the number to enter to exit).

[toast9]

I also have this loop going too

while (num < 0){
      
      cout << "Enter a Number: " << endl;
      cin >> num;
      
      if(num == -1){
         exit(1);
      }
      else{
         cout << "Invalide Number" << endl <<
         "The number must be a whole number" << endl;
      }
   }

[toast9]

I put it all in the for loop instead of a do while loop. I'm not sure how to do a dowhile loop. Is it the same as a do loop? I do have a new problem. If I type in 0 I get this: (lldb) No clue what it means. If 0 is typed in the answer should be one, not sure what it's doing.

[toast9]

I change the loop to a do loop but I still have one problem. When I enter in 0 the code just exits. I'm not sure why.

int num;             //Variables
   int multi = 0;
   int answer = 1;
   
   cout << "Enter -1 to exit" << endl;
   cout << "Enter a Number: ";
   cin >> num;
   
   do{
      multi++;
      answer = answer * multi;
      cout << answer << endl;
      
      //To start over the loop and enter in a new number
      
      if (num == multi){
         
         cout << "Enter a Number: ";
         cin >> num;
         multi = 0;
         answer = 1;
      }

      //For negative numbers and how to exit (-1)
      
      while (num < 0){
         
         if(num == -1){
            exit(1);
         }
         else{
            cout << "Invalide Number" << endl <<
            "The number must be a whole number" << endl;
            cout << "Enter a Number: ";
            cin >> num;
         }
      }
      
   }while (num > multi);
}

[The illusionist mirage]

toast9 wrote:

I change the loop to a do loop but I still have one problem. When I enter in 0 the code just exits. I'm not sure why.

You have initialized multi as 0. And in your do-while loop, you check whether num is greater than multi. So, if you input num as 0, the while test condition evalutates as false, hence exiting your loop.

[toast9]

i changed it to while num is greater than equal to and it still exits.

[The illusionist mirage]

Show the exact and full code you are using right now.

EDIT:

Anyways, your while test condition is still incorrect because,

if num = 0, and multi = 0,

while (num > multi) and while (num < multi) both evaluate as false ;)