Assist with while looping

[oy721hU5]

Please lend me a helping hand. I have printed six different series of numbers. The requirement was to only use one and only one single while loop.

  #include <stdio.h>
#include <stdlib.h>

int main()
{
    int k;
    k = 0;
    while (k < 10)
    {
        if (k < 9)
        {
            printf("%5d,",   k+1         ); // these numbers should be a line by itself
            printf("%5d,",   2*k+2       ); // these numbers should be a line by itself
            printf("%5d,",   3*k+3       ); // these numbers should be a line by itself
            printf("%5d,",   10*k+10     ); // these numbers should be a line by itself
            printf("%5d,",    2*k+1      ); // these numbers should be a line by itself
            printf("%5d,",   (k+1)*(k+1) ); // these numbers should be a line by itself
        }
        else if (k = 9)
        {
            printf("%5d",   k+1         ); // these will simply print the last number of the loop, each correspond to one line
            printf("%5d",   2*k+2       ); // these will simply print the last number of the loop, each correspond to one line
            printf("%5d",   3*k+3       ); // these will simply print the last number of the loop, each correspond to one line
            printf("%5d",   10*k+10     ); // these will simply print the last number of the loop, each correspond to one line
            printf("%5d",   2*k+1       ); // these will simply print the last number of the loop, each correspond to one line
            printf("%5d",   (k+1)*(k+1) ); // these will simply print the last number of the loop, each correspond to one line

        }
        else{}
        k = k+1;
    }
}

The output must look similar to this:

1,   2, 3, 4,  5,  6,  7,  8,   9, 10
2,   4, 6, 8, 10, 12, 14, 16,  18, 20
3,   6, 9, 12, 15, 18, 21, 24, 27, 30
10, 20, 30, 40, 50, 60, 70, 80, 90, 100
1,  4, 9, 16, 25, 36, 49, 64, 81, 100

But I have an entire different chaos of numbers. Please help me.

[coder777]

if you want to print out 6 lines you need to cycle 6 times more:

while (k < (10 * 6))

use a switch to separate the lines:

switch(k / 10)
{
case 0:
            printf("%5d",   k+1         ); // these numbers should be a line by itself
            break;
case 1:
            printf("%5d",   2*k+2       ); // these numbers should be a line by itself
            break;
...
}

to print the comma and the end of line do this:

if(k % 10)
            printf(", ");
else if(k > 0)
            printf("\n");

[fahmankhan75]

Was just reviewing over the some of these questions on the forum. Just a beginner, what does "%5d" do? I thought it was suppose to print out a message on the console. Also is printf same as cout?

[TheIdeasMan]

@fahmankhan75,

Have a look in the reference section at the top left of this page.

[Manga]

line 19 has an error.

should use two equal signs.


You are using only 'c' code here.

I am not good with c style code but here is the solution with c++

#include <iostream>
using namespace std;

int main() {
	int a=1, b=0, c=0;

	while(true) {
		if(c==0) {
			cout << a+b << ", ";
			b++;
		}
		if(b==10 && c==0) {
			cout << endl;
			c++;
			b=2;
		}
		if(c==1) {
			cout << a*b << ", ";
			b=b+2;
		}
		if(b==22 && c==1) {
			cout << endl;
			c++;
			b=3;
		}
		if(c==2) {
			cout << a*b << ", ";
			b=b+3;
		}
		if(b==33 && c==2) {
			cout << endl;
			c++;
			b=10;
		}
		if(c==3) {
			cout << a*b << ", ";
			b=b+10;
		}
		if(b==110 && c==3) {
			cout << endl;
			c++;
			b=1;
		}
		if(c==4) {
			cout << a << ", ";
			b=b+2;
			a=a+b;
		}
		if(a>100 && c==4) {
			cout << endl;
			break;
		}

	}

	cin.get();
	return 0;
}

the secret to using only one while loop is to work with 3 variables.
the first is your starting value, the second is to change the first with logical pattern and the third controls flow in the loop.

[ShodanHo]

Change line 19:
else if (k = 9)
to:
else if (k == 9)