read more than one line

[brijay09]

Write your question here.
I am trying to find a way to make the program read more than one line..

  #include<iostream>
using namespace std;
int main()
{
	   int c;
	   c = cin.get();
	   while ( ! cin.eof())
	   {
	   	   cout.put(c);
	   	   c= cin.get();
	   	   
	   }
}

[LB]

How will you know if it worked if there is no output?

[brijay09]

right now it reads the input from the user then after hitting return it prints out the same thing. i'm trying to find a way to make it read everything up until the user enters a blank line.

[Josue Molina]

Try this out:

#include <iostream>
#include <string>

int main()
{
    std::string input;

    std::getline(std::cin, input);

    while (input != "")
    {
        std::cout << input << std::endl;
        std::getline(std::cin, input);
    }

    return 0;
}

[brijay09]

This works for normal input/output but the reason I'm using int c is because I'm planning on shifting the letters forward by 5.

[Josue Molina]

What are you trying to create, a Caesar cipher?

[brijay09]

Yes. I'm using cout.put() to print the result.

[Josue Molina]

The code I gave you does not need to be changed too much:

#include <iostream>
#include <string>

int main()
{
    std::string input;

    std::getline(std::cin, input);

    while (input != "")
    {
        for (int i = 0; i < input.length(); i++)
        {
            if (input[i] >= 'a' && input[i] <= 'z')
            {
                input[i] = (input[i] - 'a' + 5) % ('z' - 'a' + 1) + 'a';
            }
            if (input[i] >= 'A' && input[i] <= 'Z')
            {
                input[i] = (input[i] - 'A' + 5) % ('Z' - 'A' + 1) + 'A';
            }
        }

        std::cout << input << std::endl;
        std::getline(std::cin, input);
    }

    return 0;
}

This program will only shift the letters a - z and A - Z.

[brijay09]

That works! Thank you.

[Josue Molina]

I just made a change in lines 16 and 20.