Tell me how to add colors.

[oy721hU5]

Hello fellow programmers,

I have started to program in C, just recently. Do any of you guys know how to add colors to the lines. I would like to do this to make my code look more than just black and white.

#include <stdio.h>
#include <stdlib.h>
#include <math.h>


int main()
{

    system("cls");

    int A, B, C, D, E;

    A = 1;
    B = 2;
    C = 3;
    D = 4;
    E = 5;


    printf("\n\n\t     The value of (AA+BB)/(CC+DD)                 = %10d",  ((A*A + B*B)/(C*C + D*D)),         "\n" );
    printf("\n\n\t     The value of (AA + BB - CC)/(2AB)            = %10d",  (A*A + B*B - C*C)/(2*A*B),         "\n" );
    printf("\n\n\t     The value of (A(B-C)(C-D)(D-E))/(A+B+C+D+E)  = %10d",  (A*(B-C)*(C-D)*(D-E))/(A+B+C+D+E), "\n" );
    printf("\n\n\t     The value of (A^3 - B^3)/(C^3 + D^3)         = %10d",  (A*A*A - B*B*B)/(C*C*C + D*D*D),   "\n" );

    printf("\n\n\n\n\n\n\n");


}

[Dy7SLyTq]

what os are you you running? and i dont think , ((A*A + B*B)/(C*C + D*D)), "\n" will work

[oy721hU5]

Windows 7. I am using code::blocks to compile and run and it works well.

[nvrmnd]

try to look at this forum:

http://www.cplusplus.com/forum/beginner/5830/

[maeriden]

The reason why ((A*A + B*B)/(C*C + D*D)) doesn't work is because it evaluates to 5 / 25. Since they are integers the division equals to 0 with a remainder of 25.

[Dy7SLyTq]

i was more talking about the "\n" at the end, because if i remember right thats not how printf works

[cire]

In this case the "\n" is likely to just be ignored by printf. Some implementations may warn that the number of arguments don't match the number of specifiers in the format string.

[Dy7SLyTq]

i know that it would compile, because its just being passed to the ..., but i wanted to bring that to his attention