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Switch statment in a while loop

Richard Harris (11)
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I have to modify a program I already wrote to evaluate a "Union code" A,B or C in a while loop. The program I am modifying already has the code being evaluated by a switch statement. How do I get my switch statement to function properly inside of a while loop??? I tried all night until I fell asleep from looking at the screen with no more fresh ideas. Help would be appreciated.

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 #include <iostream>

#include <string>

#include <vector>

#include <iomanip>

#include <cmath>

#include <algorithm>
#include<conio.h>
using namespace std ;

int main ()

{

vector<string>Names;
vector<double>Hours;
vector<double>Payrate;
vector<char>Union;
vector<double>Uniondues;

double dues;
char code;
double hrs;
double grade;

string EmID;



cout<<"\t\t\t Work flow is a profitable practice.  \n"<<
	"\t\t\t Let's get these folks paid!!\n";




for (int i= 0;i<3;i++)
	
	
	

{	cout<<  " Enter the students name.\t";
 
cin>>EmID;
Names.push_back(EmID);

	

cout<< "Hours worked?";

cin>>hrs;

while
	(hrs<0 || hrs>=60)
	
	{(cout<<  "Hours exceed Maxium Allowable work Hours.    Child labor pentalities may result.   P.S..  YOUR FIRED!!!!   \n")
	;
cout<< "\n";
cout<< "\n";


cout<< "\n\t\t\t.. Enter Hours worked.";
cin>>hrs;}

 
	
	Hours.push_back(hrs);



cout<< " Enter employee payrate.\t";
cin >> grade;

while
	(grade<7.50 || grade>45.00)
	
	{(cout<<  "Payrate not withing Allowable Range.");
cout<< "\n";
cout<< "\n";

cout<< "\n\t\t\t.. Enter Valid Payrate.";
cin>>hrs;}
Payrate.push_back(grade);



	cout<< "what is code?";
	cin>> code;

	
	while (cin>>code)

	
	
	{  switch (code)

		

		{	case 'A': case 'a':
			
			dues= 25.00;
			
			
			
			
			

		        break;
	
			case 'B' : case 'b':
		
			dues= 50.00;

		
			break;

			
				
			case 'C' : case 'c':
		
			dues= 75.00;

		
			break;

			default: 

			cout<<" Inputted union code is invalid.\n";
			cout<<" Enter valid Union Code\n";
			cin>>code;
			// loop
			continue;

	
	}}

Union.push_back(code);
Uniondues.push_back(dues);


	
}






	




// print names

for (int i= 0; i<3; i++)
	{
		
	cout<<Names[i]<<endl;
	cout<<Hours[i]<<endl;
	cout<<Uniondues[i]<<endl;
	
}

system ("pause");
return 0;
}
Last edited on
closed account (jwkNwA7f)
Here: while (code= A You forgot the closing parenthesis, ), and you forgot the opening curly bracket, {.

EDIT: Wrong character.
Last edited on
MikeyBoy (5631)
Just put it inside the loop, like you'd put any other bit of code.

Your code would be much easier to read - for you and us - if you'd adopt a sensible indentation style.

Presumably, your compiler is giving you error messages about line 94, which looks like a half-finished line to me.
Richard Harris (11)
The Actual issue is revised and above. The thing is this. When I run it, it goes through the code up until the point AFTER it asks me for the Union Code , then it doesnt do Anything; which a clear indication that is has been left without a command; A problem I think is in the calling of the functions.
MikeyBoy (5631)
Please could you put your code in code tags, to make it more readable?
closed account (jwkNwA7f)
@MikeyBoy They did, but they didn't put the closing tag for them.
Richard Harris (11)
okay
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