Write your question here.
1) I need to sum the values from 1 to N using a for loop
2) I need to input two values and find their range
3) I need to input a number to a power
There is a condition to 1) that is must be a positive that I enter
I can do 2) by just ordering the numbers and subtracting right?
and for 3) I need it to be a positive power
When I run this it with something that does not fit the conditions it will let me re-enter but not re-calculate. also when it lets me reenter for the first one it shows the prompt for the second one. PLEASE HELP i am so lost :(
it should print out like this:
Please input a #>1: -3
Please input a #>1: -8
Please input a #>1: 0
Please input a #>1: 2
The sum of integers from 1 to 3 is: 6
Please input 2 numbers: -1 9
The interval between -1 and 9 is: 10
Please input two numbers(no negatives): 4 -8
Please input two numbers(no negatives): 4 0
The product of 4 ^ 0 is: 1
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38
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#include <iostream>
using namespace std;
int main()
{
int num, sum=0, i;
cout<<"Please input an integer greater than or equal to 1: ";
cin>>num;
if (num<1)
cout<<"Please input an integer greater than or equal to 1: ";
else
{
for(i=0; i<=num; i++)
sum+=i;
cout<<"The sum of integers from 1 to "<< num <<" is: "<< sum << endl;
}
int n,p,r=1;
cout<<"Please input two integers, the second must be non-negative: " << endl;
cin>>n>>p;
while (p>1)
{
r=r*n;
cout<<"The product of " << n << "^" << p << "is: "<< r << endl;
}
if (p<1)
cout<<"Please input two integers, the second must be non-negative: "<< endl;
cin.ignore();
cin.get();
return 0;
}
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