Hw help! parallelogram and diamond

[juskeating]

Hi, I wanted to know where to begin on this. I'm supposed to prompt the user for a number and then it should display a parallelogram and diamond. I've tried using nested for loops but I couldn't figure out the right conditions. Any help would be much appreciated. Thanks.

Here's a sample run.

Enter a number: 5

        ***** 
       ***** 
      ***** 
     ***** 
    ***** 

     *
    ***
   ***** 
  ******* 
 ********* 
  ******* 
   ***** 
    *** 
     * 
     

[condor]

Post your code(good/bad) please to see and correct it.

[condor]

Here's the code for the diamond which is slight more difficult than for the parallelogram. Try to complete that code and post it.

#include <iostream>
#include <iomanip>

int main()
{
	using std::cin;
	using std::cout;
	using std::setw;
	
	int n;
	cout << "Enter a number: ";
	cin >> n;
	
	//...Here was the code for the parallelogram :).
	
	//...And here's for the diamond :)).
	for(int i = 0; i < (n + 1)/2 + 1; ++i)
	{
		cout << setw(n - i + 1);
		for(int j = 0; j < 2*i - 1; j++)
			cout << '*';
		cout << '\n';
	}
	for(int i = (n + 1)/2; i > 0; --i)
	{
		cout << setw(n - i + 2);
		for(int j = 2*i - 3; j > 0; --j)
			cout << '*';
		cout << '\n';
	}
}

The output:

Enter a number: 10
          
         *
        ***
       *****
      *******
     *********
      *******
       *****
        ***
         *

[juskeating]

Thanks condor. I wasn't able to get the parallelogram right. Here's my code.

for(int i=num; i>=0; i--)
		{
			for(int j=0; j<num; j++)
				{
					if(j<i)
					{
						cout << " ";
					}
					else
					{
						cout << "*";
					}
				}
			cout<<endl;
		}
	for(int i=0; i<num; i++)
		{
			for(int j=i; j<num; j++)
				{
					cout << "*";
				}
			cout << endl;
		}

[condor]

Here's the complete code (slight modified):

#include <iostream>
#include <iomanip>

using namespace std;

int main()
{
	int i, n;
	char w;
	cout << "Enter a number: "; // it is nice from 11 to 25.
	cin >> n;
	cout << "Used character: "; // any character : a..z, !. -, _, |, \, /, * and so on.
	cin >> w;
	int s = (n + 1)/2;
	//...Here's the code for the parallelogram.
	for(int i = n; i > 0; --i)
	{
		cout << setw(i + 4);
		for(int j = 0; j < n; ++j)
			cout << w;
		cout << '\n';
	}
	//...And here's for the diamond.
	for(i = 0; i < s + 1; ++i)
	{
		cout << setw(s + 5 - i);
		for(int j = 0; j < 2*i - 1; ++j)
			cout << w;
		cout << '\n';
	}
	for(i = s; i > 0; --i)
	{
		cout << setw(s + 6 - i);
		for(int j = 2*i - 3; j > 0; --j)
			cout << w;
		cout << '\n';
	}
	// system ("pause"); 
}

Hope this helps.
Output(sample):

Enter a number: 11
Used character: o
              ooooooooooo
             ooooooooooo
            ooooooooooo
           ooooooooooo
          ooooooooooo
         ooooooooooo
        ooooooooooo
       ooooooooooo
      ooooooooooo
     ooooooooooo
    ooooooooooo
          
         o
        ooo
       ooooo
      ooooooo
     ooooooooo
    ooooooooooo
     ooooooooo
      ooooooo
       ooooo
        ooo
         o

[juskeating]

Thanks, what does it mean when you use setw?

[condor]

setw(n) sets the field width to be used on output operations. (n = number of characters to be used as field width.) For more info see:

http://www.cplusplus.com/reference/iomanip/setw/?kw=setw

Happy programming! ;)

[cyphor]

can it be done without the setwidth?

[condor]

Try with std::setfill().

http://www.cplusplus.com/reference/iomanip/setfill/?kw=setfill