help in a program
Sep 12, 2013 at 10:34am UTC
Why is 'break' misplaced in this program?
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#include <iostream.h>
#include <conio.h>
#include <stdlib.h>
#include <process.h>
void main()
{clrscr();
int p, q, r, i;
i=1;
l1:
if (i<=3)
{p=random(10);
q=random(10);
r=random(10);
cout<<p<<q<<r;
i++;
if (p==7&&q==7&&r==7)
{cout<<"winner" ;
break ;
}
else
{cout<<"try again" ;
goto l1;
}
}
getch();
}
Sep 12, 2013 at 10:42am UTC
Because break is used with loops (for, while, do while) and switch and you don't have any.
Sep 12, 2013 at 10:46am UTC
so what can i use here?
Sep 12, 2013 at 10:48am UTC
Simply because break is not allowed inside if, break is only needed on loops, switch..case etc..
if you want to end your program when
( p==7 && q==7 && r==7)
then you have to do something like this:
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if (p==7&&q==7&&r==7) {
cout<<"winner" ;
getch();
exit ( 0 );
}
or
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if (p==7&&q==7&&r==7) {
cout<<"winner" ;
getch();
return 0;
}
but in the 2nd example you have to change the return type of main to int instead of void and you don't need getch() at the end of your program
Sep 12, 2013 at 10:55am UTC
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int main()
{
int p, q, r, i;
i=1;
for (i = 0; i < 3; i++)
{
p=random(10);
q=random(10);
r=random(10);
cout<<p<<q<<r;
i++;
if (p==7 && q==7 && r==7 )
{
cout<<"winner" ;
break ;
}
else
{
cout<<"try again" ;
}
}
}
Sep 12, 2013 at 10:59am UTC
nice ideas but I did something using goto command:)
Can you tell me how to do that program using for, while, or do while loop?(any one)
Thanks in advance:)
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