c++ bit shifting

[k31453]

this code give us this characters ‘-’, ‘-’, ‘-’, ‘+’.

To access the next
character, we need to “shift” the 32-bit integer value by 8 bits to fetch the next character.
This is a simple integer division by 256.
dont know what to do !!

sample data input: 757935403

  int main()
{
	int a;
	cout << "what is your code?" << endl;
	cin >> a;
	do {
	int b = a % 256;
	cout <<char(b);
	int c = b >> 8;
	cout << char (c);
	}while (a != 0);

	return 0;
}

[Chervil]

    while (a != 0)
    {
        char b = a & 0xff;
        cout << b;
        a >>= 8;
    }

[k31453]

okay I got that now We need to add a test: if the value of
the decoded character is equal to 0x0A, then we output ‘\n’ (or endl). Otherwise, we
output just the decoded character.

so this is my code

int a;
	cout << "what is your code?" << endl;
	cin >> a;
	do {
	int b = a % 256;
	if (b == 0x0A){
		cout << endl;
	}
	cout <<char(b);
	int c = a/256;
	a = c;
	}while (a != 0);