variable char problem in switch loop

[ephekt]

I have to write a sort of blackjack program using a switch loop, I have most of it done but it needs to take letters for the face cards upper and lower case which all = 10, and have a condition for the ace being 1 or 11 (which ever helps the user more). The book gave a hint that the cards should be var. type char, but everything i tried doesn't work. So my question is how do I implement this? Do I state it some how in each case or at the start of my program?
Thank you for your help.

 #include <iostream>
using namespace std;

int main( )
{
    char ans, NumberOfCards;  
    int Sum, CardValue1, CardValue2, CardValue3, CardValue4, CardValue5;
       do
       {        
       cout << "Please input the number of cards 2, 3, 4 or 5\n";
       cin >> NumberOfCards;
       
       switch  (NumberOfCards)
       {
        case '2': 
                cout << "First Card" " ";
                cin  >>  CardValue1;
                cout << "Second Card" " ";
                cin >> CardValue2;
                Sum = CardValue1 + CardValue2;
                cout << "Your Score is" " " << Sum << " \n";
                break;        
         
         case '3':       
                cout << "First Card" " ";
                cin  >>  CardValue1;
                cout << "Second Card" " ";
                cin >> CardValue2;
                cout << "Third Card" " ";
                cin  >>  CardValue3;
                Sum = CardValue1 + CardValue2 + CardValue3;
                cout << "Your Score is" " " << Sum << " \n";
                break;
        
         case '4':
                cout << "First Card" " ";
                cin  >>  CardValue1;
                cout << "Second Card" " ";
                cin >> CardValue2;
                cout << "Third Card" " ";
                cin  >>  CardValue3;
                cout << "Forth Card" " ";
                cin >> CardValue4;
                Sum = CardValue1 + CardValue2 + CardValue3 + CardValue4;
                cout << "Your Score is" " " << Sum << " \n";
                break;
          
          case '5':
                cout << "First Card" " ";
                cin  >>  CardValue1;
                cout << "Second Card" " ";
                cin >> CardValue2;
                cout << "Third Card" " ";
                cin  >>  CardValue3;
                cout << "Forth Card" " ";
                cin >> CardValue4; 
                cout << "Fifth Card" " ";
                cin >> CardValue5;
                Sum = CardValue1 + CardValue2 + CardValue3 + CardValue4 + CardValue5;
                cout << "Your Score is" " " << Sum << " \n";
                break;
          
          default:
                cout << "Incorrect Input of Cards\n";      
           }              
           if (Sum > 21)
           {
           cout << "Busted\n";
           }
           else
           {
           cout << "Winner\n";
           }                
        cout << "would you like to play another hand?\n";
        cout << "Press y or n\n";
        cin >> ans;

   } while(ans == 'y' or ans == 'Y'); 

system("Pause");
return 0;
}

[Josue Molina]

I ask this out of curiosity: do you know how to nest loops and use arrays?

[ephekt]

I have covered nesting but not arrays. Im pretty sure a nested if else in each case is the answer but not sure how to make it happen.

[Josue Molina]

Study this:

#include <iostream>

using namespace std;

int convert(char);

int main()
{
    char ans;

    do
    {
        cout << "Enter the number of cards: " << endl;
        int numberOfCards;
        cin >> numberOfCards;

        char* cards = new char[numberOfCards];

        for (int i = 0; i < numberOfCards; i++)
        {
            cout << "Enter card " << i << ": ";
            cin >> cards[i];
        }

        int sum = 0;

        for (int i = 0; i < numberOfCards; i++)
        {
            sum += convert(cards[i]);
        }

        cout << "Your total is: " << sum << endl;

        if (sum > 21)
        {
            cout << "Busted..." << endl;
        }
        else
        {
            cout << "Winner!" << endl;
        }      

        cout << "Would you like to play another hand?" << endl;
        cout << "Type y or Y to continue: ";
        cin >> ans;
    } while(ans == 'y' || ans == 'Y');

    delete [] cards;

    cin.get();
    return 0;
}

int convert(char c)
{
    switch (c)
    {
        case '2':
            return 2;
        case '3':
            return 3;
        case '4':
            return 4;
        case '5':
            return 5;
        case '6':
            return 6;
        case '7':
            return 7;
        case '8':
            return 8;
        case '9':
            return 9;
        case 't':
        case 'T':
            return 10;
        case 'j':
        case 'J':
            return 11;
        case 'q':
        case 'Q':
            return 12;
        case 'k':
        case 'K':
            return 13;
        case 'a':
        case 'A':
            return 14;
        default:
            return 0;
    }
}

It uses arrays and loops and lets you input any number of cards you want (because of this).

[ephekt]

Thank you for you help, I certainly will study this. It uses some things i haven't covered in my class yet but get the gist. I think the main thing i was missing was the int convert char with individual cases for each input.