Can't inline a 1 line void function!

[Codeez]

I have this simple function in a file:

generic.cpp

#include <iostream>
#include <string>

inline void clearScreen()
{
    std::cout << std::string( 30, '\n' ) << std::endl;
}

Now when I simply call this, clearScreen();, in main.cpp, I get this:

* warning: inline function 'void clearScreen()' used but never defined [enabled by default]|
* error: undefined reference to `clearScreen()'|

I've also forward declared it in main: inline void clearScreen();. It works fine without the inline keyword, not sure why it doesn't like it though?

[Zhuge]

I'd think you shouldn't have to forward declare it at all. Just include the entire inline definition in the header; if you put it in a separate source file then it can't be inlined.

[Codeez]

Ok, thanks for clearing that up, that worked.

Cheers!