Aug 5, 2013 at 11:50pm UTC
Can someone explain me how the for loops work in this piece for code real quick?
int k;
for(i=1;i<=5;i++)
{
for(j=5;j>i;j--)
cout<<' ';
for(k=1;k<=i;k++)
cout<<'*';
cout<<endl;
}
cout << endl;
for(i=1;i<=5;i++)
{
for(j=5;j>i;j--)
cout<<' ';
for(k=1;k<2*i;k++)
cout<<'*';
cout<<endl;
}
cout << endl;
for(i=1;i<=5;i++)
{
for(j=5;j>i;j--)
cout<<' ';
for(k=1;k<2*i;k++)
cout<<i;
cout<<endl;
}
cout << endl;
int l;
for(i=1;i<=5;i++)
{
for(j=5;j>i;j--)
cout<<' ';
for(k=i;k>=1;k--)
cout<<k;
for(l=2;l<=i;l++)
cout<<l;
cout <<endl;
}
Aug 5, 2013 at 11:58pm UTC
It won't; you need to declare your variables 'i' and 'j'. But after you have that straightened out, the first portion initiates a variable, the second evaluates a condition before each iteration of the loop and the last statement executes a command at the completion of every iteration.
Aug 6, 2013 at 12:13am UTC
A formatted code is easy to read than unformatted. For example
1 2 3 4 5 6 7 8
int k;
for ( i = 1; i <= 5; i++ )
{
for ( j = 5; j > i; j-- ) cout << ' ' ;
for ( k = 1; k <=i; k++ ) cout<< '*' ;
cout<<endl;
}
cout << endl;
I think that the autor of the code tried to print out a pyramid. However the output is the following
Edit: Oh, I am sorry. The output is indeed a pyramid
P.S. The output can not be formatted exactly the same way as in the console.
Last edited on Aug 6, 2013 at 12:17am UTC