pointer to object

[ankushnandan]

Write your question here.

  #include<iostream>

using namespace std;

class TestNULL{
public:
	void print()
	{
		cout<<"\n In Print Function";
	}
};


int main()
{
	TestNULL * ptr = NULL;
	ptr->print();           //Why it didn't break here???
	return 0;
}

Output of above code is In Print Function

ptr->print(); why compiler didnt complain at this line??

[vlad from moscow]

The compiler does not have code that tries to access the memory at address 0. In fact the code that calls the function

ptr->print();

is equivalent to

print( this );

that in turn is equivalent to

print( NULL );

As the argument of the function is not used there is no any problem.

[ankushnandan]

yes i got it... thanks vlad from moscow