Trying to loop craps game multiple times to find house advantage
Jul 23, 2013 at 5:20pm UTC
The craps game below is correct...I just wanted to know what I would need to do to loop the game, say, 1000 times. I want to see what the house advantage would be when this game is run many times.
Thanks!
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#include <iostream>
#include <ctime>
#include <stdlib.h>
using namespace std;
int rollDice();
int main()
{
enum Status {CONTINUE, WON, LOST};
int myPoint = 0;
Status gameStatus;
srand(time(0));
int sumOfDice = rollDice();
switch (sumOfDice){
case 7:
case 11:
gameStatus = WON;
break ;
case 3:
case 4:
case 12:
gameStatus = LOST;
break ;
default :
gameStatus = CONTINUE;
myPoint = sumOfDice;
cout << "Point is: " << myPoint << endl;
break ;
}
while (gameStatus == CONTINUE){
sumOfDice = rollDice();
if (sumOfDice == myPoint)
gameStatus = WON;
if (sumOfDice == 7)
gameStatus = LOST;
}
if (gameStatus == WON)
cout << "Player wins!" << endl;
else
cout << "Player loses!" << endl;
}
int rollDice(){
int dice1 = 1 + rand()%6;
int dice2 = 1 + rand()%6;
int total = dice1 + dice2;
cout << "Player rolled " << dice1 << " and " << dice2 << " for a total of " << total << endl;
return total;
}
Last edited on Jul 23, 2013 at 5:24pm UTC
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