how to use a function with pointer parameter to print array

Jul 20, 2013 at 6:36pm
The printArray function should take in the dynamically created array and the size of the array as parameters. It should print out the contents of the array.

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  #include <iostream>
  #include <string>
  using namespace std;
  void printArray (int *, int);

  int main()
  { 
	int numStudents;
	int *movies;

	cout << "How many students were surveyed?" << endl;
	cin >> numStudents;

	while(numStudents <= -1)
	{
		cout << "Enter a positive number." << endl;
		cin >> numStudents;
	}
	movies = new int[numStudents];

	//cout << "Enter the number of movies watched by each student: ";

	for(int i = 1; i <= numStudents; i++)
	{
		cout << "Enter number of movies watched by student " << i << " : ";
		cin >> movies[i-1];

		while( movies[i-1] < 0)
		{
			cout << "Enter a positive number: ";
			cin >> movies[i-1];
		}
	}

	printArray(movies, numStudents); 

	return 0;
}

void printArray (int *, int)
{
	
	
}



My problem is that I have no idea how to write the code to print the array using pointers. I've been stuck for awhile trying to figure it out.
Jul 20, 2013 at 8:16pm
Well, that's only a skeleton, it doesn't even have names for the parameters. What code have you actually tried so far inside that function?
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