Choice Problem
When I do a sum and than it tells me would u like to try again and when i type n it does not work it goes to funtion main again..THank you..
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#include <iostream>
using namespace std;
int main();
int adding ()
{
int n1, n2;
cout << "\nType two new numbers to add: \n" << endl;
cin >> n1 >> n2;
cout << n1 << " + " << n2 << " equels " << n1 + n2 << endl;
char choice = 'a';
cout << "\nWould you like to try again \ny for yes, n for no: " << endl;
cin >> choice;
if (choice = 'y' || choice == 'Y') {
main ();
} else {
cout << "\nBye Bye" << endl;
}
return 0;
}
int subtracting ()
{
int n1, n2;
cout << "\nType two new numbers to subtract: \n" << endl;
cin >> n1 >> n2;
cout << n1 << " - " << n2 << " equels " << n1 - n2 << endl;
char choice = 'a';
cout << "\nWould you like to try again \ny for yes, n for no: " << endl;
cin >> choice;
if (choice = 'y' || choice == 'Y') {
main ();
} else {
cout << "\nBye Bye" << endl;
}
return 0;
}
int multiplycation ()
{
int n1, n2;
cout << "\nType two new numbers to multiply: \n" << endl;
cin >> n1 >> n2;
cout << n1 << " * " << n2 << " equels " << n1 * n2 << endl;
char choice = 'a';
cout << "\nWould you like to try again \ny for yes, n for no: " << endl;
cin >> choice;
if (choice = 'y' || choice == 'Y') {
main ();
} else {
cout << "\nBye Bye" << endl;
}
return 0;
}
int devision ()
{
int n1, n2;
cout << "\nType two new numbers to devide: \n First one bigger than second \n" << endl;
cin >> n1 >> n2;
cout << n1 << " / " << n2 << " equels " << n1 / n2 << endl;
char choice = 'a';
cout << "\nWould you like to try again \ny for yes, n for no: " << endl;
cin >> choice;
if (choice = 'y' || choice == 'Y') {
main ();
} else {
cout << "\nBye Bye" << endl;
}
return 0;
}
int main()
{
cout << "Type \na for adding \ns for subtracting \nm for multiply \nd for divide \n" << endl;
char choice = 'y';
cin >> choice;
if (choice == 'a' || choice == 'A')
{
adding ();
}
else if (choice == 's' || choice == 'S')
{
subtracting ();
}
else if (choice == 'm' || choice == 'M')
{
multiplycation ();
}
else if (choice == 'd' || choice == 'D')
{
devision ();
}
else
{
cout << "Only a,s,m,d" << endl;
}
return 0;
}
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Edited working
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#include <iostream>
using namespace std;
int adding ()
{
int n1, n2;
cout << "\nType two new numbers to add: \n" << endl;
cin >> n1 >> n2;
cout << n1 << " + " << n2 << " equels " << n1 + n2 << endl;
char choice;
cout << "\nWould you like to try again \ny for yes, n for no: " << endl;
cin >> choice;
if (choice == 'y' || choice == 'Y') {
return 1;
} else {
cout << "\nBye Bye" << endl;
return 0;
}
}
int subtracting ()
{
int n1, n2;
cout << "\nType two new numbers to subtract: \n" << endl;
cin >> n1 >> n2;
cout << n1 << " - " << n2 << " equels " << n1 - n2 << endl;
char choice;
cout << "\nWould you like to try again \ny for yes, n for no: " << endl;
cin >> choice;
if (choice == 'y' || choice == 'Y') {
return 1;
} else {
cout << "\nBye Bye" << endl;
return 0;
}
}
int multiplycation ()
{
int n1, n2;
cout << "\nType two new numbers to multiply: \n" << endl;
cin >> n1 >> n2;
cout << n1 << " * " << n2 << " equels " << n1 * n2 << endl;
char choice;
cout << "\nWould you like to try again \ny for yes, n for no: " << endl;
cin >> choice;
if (choice == 'y' || choice == 'Y') {
return 1;
} else {
cout << "\nBye Bye" << endl;
return 0;
}
}
int devision ()
{
int n1, n2;
cout << "\nType two new numbers to devide: \n First one bigger than second \n" << endl;
cin >> n1 >> n2;
cout << n1 << " / " << n2 << " equels " << n1 / n2 << endl;
char choice;
cout << "\nWould you like to try again \ny for yes, n for no: " << endl;
cin >> choice;
if (choice == 'y' || choice == 'Y') {
return 1;
} else {
cout << "\nBye Bye" << endl;
return 0;
}
}
int main()
{
int wanna;
while( 1 )
{
cout << "Type \na for adding \ns for subtracting \nm for multiply \nd for divide \n" << endl;
char choice;
cin >> choice;
if (choice == 'a' || choice == 'A')
{
wanna = adding();
if( wanna == 0)
{
break;
}
}
else if (choice == 's' || choice == 'S')
{
wanna = subtracting ();
if( wanna == 0 )
{
break;
}
}
else if (choice == 'm' || choice == 'M')
{
wanna = multiplycation ();
if( wanna == 0 )
{
break;
}
}
else if (choice == 'd' || choice == 'D')
{
wanna = devision ();
if( wanna == 0 )
{
break;
}
}
else
{
cout << "Only a,s,m,d" << endl;
}
}
return 0;
}
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Last edited on
Nope it dosnt work..
Solved by senhor on skype...i wrote
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if (choice = 'y' || choice == 'Y') {
main ();
}
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but it must be
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if (choice == 'y' || choice == 'Y') {
main ();
}
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Correct COde
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|
#include <iostream>
using namespace std;
int main();
int adding ()
{
int n1, n2;
cout << "\nType two new numbers to add: \n" << endl;
cin >> n1 >> n2;
cout << n1 << " + " << n2 << " equels " << n1 + n2 << endl;
char choice = 'a';
cout << "\nWould you like to try again \ny for yes, n for no: " << endl;
cin >> choice;
if (choice == 'y' || choice == 'Y') {
main ();
} else {
cout << "\nBye Bye" << endl;
}
return 0;
}
int subtracting ()
{
int n1, n2;
cout << "\nType two new numbers to subtract: \n" << endl;
cin >> n1 >> n2;
cout << n1 << " - " << n2 << " equels " << n1 - n2 << endl;
char choice = 'a';
cout << "\nWould you like to try again \ny for yes, n for no: " << endl;
cin >> choice;
if (choice == 'y' || choice == 'Y') {
main ();
} else {
cout << "\nBye Bye" << endl;
}
return 0;
}
int multiplycation ()
{
int n1, n2;
cout << "\nType two new numbers to multiply: \n" << endl;
cin >> n1 >> n2;
cout << n1 << " * " << n2 << " equels " << n1 * n2 << endl;
char choice = 'a';
cout << "\nWould you like to try again \ny for yes, n for no: " << endl;
cin >> choice;
if (choice == 'y' || choice == 'Y') {
main ();
} else {
cout << "\nBye Bye" << endl;
}
return 0;
}
int devision ()
{
int n1, n2;
cout << "\nType two new numbers to devide: \n First one bigger than second \n" << endl;
cin >> n1 >> n2;
cout << n1 << " / " << n2 << " equels " << n1 / n2 << endl;
char choice = 'a';
cout << "\nWould you like to try again \ny for yes, n for no: " << endl;
cin >> choice;
if (choice == 'y' || choice == 'Y') {
main ();
} else {
cout << "\nBye Bye" << endl;
}
return 0;
}
int main()
{
cout << "Type \na for adding \ns for subtracting \nm for multiply \nd for divide \n" << endl;
char choice = 'y';
cin >> choice;
if (choice == 'a' || choice == 'A')
{
adding ();
}
else if (choice == 's' || choice == 'S')
{
subtracting ();
}
else if (choice == 'm' || choice == 'M')
{
multiplycation ();
}
else if (choice == 'd' || choice == 'D')
{
devision ();
}
else
{
cout << "Only a,s,m,d" << endl;
}
return 0;
}
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Last edited on
In C++, you may not call main. The standard forbids it.
In C++, you may not call main. The standard forbids it.
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I said that to him lol.
But how come it works?
Why do you not get hit by a truck every time you wander into a street while blindfolded?
Undefined behavior may appear to do what you expect. It is still undefined behavior.
@cire
OK i get it
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