5) Declare an int array with 5 spaces
-Note: an array is similar to a pointer and can be used as one
--The name of the array, or numbers in your case, is also the pointer to the first element
6) Declare a pointer that points to an int
7) Assign the location of the first value in numbers to p; then access that location and assign 10 to it
8) Have p point to the next location, or &(numbers[1]); then access that location to assign 20 to it
9) Have p point to the location of the third element in numbers; then assign 30 to that location
-Note: p = &numbers[2]; is equivalent to p = (numbers + 2); and, specifically on this line, p++;
10) Now have p point to the location of numbers[3]; missing "p" in "*=40" I am presuming
11) Have p again point to the first element of numbers; however, access the location offset by 4 (so numbers[4]) and assign 50 to that.
-Note: *(p+4) is equivalent to *(numbers+4) and numbers[4]
12-13) Print the new contents of the numbers array, which should turn out to be: 10, 20, 30, 40, 50.