Problem in Template Classes

[junaidkhan2013]

1:- In Template class : template <class khan, class khan1, class khan2> if I removed the other two arguments like template<class khan> and then i modify the two functions like below so it works like an ordinary functions,

Below Program Works Fine like and ordinary class and functions:

 #include <iostream>
using namespace std;

class generic {
    public:
template <class khan> //Generic Type of data//
khan add(khan a, khan b ,khan c){
  khan d = a+b+c;
   cout <<"Function 1:" <<endl;
  cout <<"Integers Addition: = " <<d <<endl;
  cout<<"\n";
  return d;
}

double add1(double a, double b ,double c){
 double d = a+b+c;
 cout <<"Function 2:" <<endl;
  cout <<"Double Inegers Addition: = " <<d <<endl;
   cout<<"\n";
  return d;
}

float per(float a, float b ,float c){
 float d = a+b+c;
 float per = 0;
 per = d*100.0/300;
 cout <<"Function 3:" <<endl;
cout <<"Total Marks are = " << d  <<endl;
cout <<"Percentage = " << per <<"%"  <<endl;
  return per;
}
};

int main()
{
    generic g;
    g.add(5,5,5);
    g.add1(5.5,5.5,5.5);
    g.per(78,89,89);


    return 0;
}

Program :2 Which doent work: Problem/Output= "Does Not Name A type or Mis match call to a Function""" Please any1 sort it out...and guide me where i m making mistakes and mess....

  #include <iostream>
using namespace std;

class generic {
    public:
template <class khan, class khan1, class khan2> //Generic Type of data//

khan add(khan a, khan b ,khan c){
  khan d = a+b+c;
   cout <<"Function 1:" <<endl;
  cout <<"Integers Addition: = " <<d <<endl;
  cout<<"\n";
  return d;
}

khan1 add1(khan1 a, khan1 b ,khan1 c){
 khan1 d = a+b+c;
 cout <<"Function 2:" <<endl;
  cout <<"Double Inegers Addition: = " <<d <<endl;
   cout<<"\n";
  return d;
}

khan2 per(khan2 a, khan2 b ,khan2 c){
 khan2 d = a+b+c;
 khan2 per = 0;
 per = d*100.0/300;
 cout <<"Function 3:" <<endl;
cout <<"Total Marks are = " << d  <<endl;
cout <<"Percentage = " << per <<"%"  <<endl;
  return per;
}
};

int main()
{
    generic g;
    g.add(5,5,5);
    g.add1(5.5,5.5,5.5);
    g.per(78,89,89);


    return 0;
}

[kevinkjt2000]

I think you are confused on the proper use of template syntax. Please take time to read this link and then let us know if you make any progress.
http://www.cplusplus.com/doc/tutorial/templates/

[junaidkhan2013]

Thank you kevinKjt2000,, yeah sorry i was little bit confused ,, but anhow i got now some idea about it... but now i have another problem:
please check it out and correct it,,

Problem When i run this program at the end after displaying LETS PLAY THE GAME it show zero so how to remove that Zero, I used return 1 so it showed 1 and then i removed the return statement in my function/method name Print() then i showed a huge value dont know whats the problem.......

#include <iostream>

using namespace std;
template <class T>
class khan{
T first, second;
public:
    khan(){
        T a,b;
    cout<<"Enter Vale for a"<<endl;
    cin>>a;
    cout<<"Enter Vale for b"<<endl;
    cin>>b;
    first  = a;
    second = b;
    }
    T compare();
    T print();
};

template <class T>
T khan<T>::compare(){
if(first>second){
        T i= first+2; //return type is T which is now Integer in this case//
        return(i);}
else{
        if(first<second){
        T j= first-2; //return type is T which is now Integer in this case//
        return(j);}
}
}

template <class T>
T khan<T>::print(){
cout<<"\nLets Play the Game"<<endl;
return 0 ;
}


int main()
{
    khan <int> k;
    cout<<k.compare();
    cout<<k.print();
}

[ne555]

cout<<k.print();
¿what do you think that does?

Easier, ¿what would code<<foo(); do?

[junaidkhan2013]

Ne555 sorry I didn,t get you,, would you please tell me how exactly to implement the code<<foo(),,, I used cout<<k.print() to call the Print() function i used above,,, please guide me ...

[OxBADC0DE]

Don't use cout<<k.print() instead just do k.print(). Reason: in the x::print() method it already has the cout, so there's going to be an error repeating the ostream. Its like saying std::cout<<std::cout<<"blah";

[ne555]

Oops, sorry I made a typo
What I mean was cout<<foo();
that would execute `foo()', and then print to screen whatever foo() returns (like in cout << k.compare();

So analyze what cout<<k.print(); is doing.
`k.print()' prints a message and returns 0, that it's printed by cout.


If you don't want to output the result, then don't output the result (¿why are you returning anything, btw?)