Generating 3 random numbers

[Bv202]

Hi,

I want to generate 3 random numbers by calling a function which generates a number 3 times. The function is:

int randomgetal()
{
	int getal;
	srand(time(0));

	getal = 2+ rand() % 6;

	return getal;
}

Very easy. First of all, can anyone explain me the meaning of (0) in the time() function in there? I got it from a tutorial. Also, the compiler gives me this warning:
warning C4244: 'argument' : conversion from 'time_t' to 'unsigned int', possible loss of data

Why is that and is there a way to solve it?

Now my real problem... just calling this function 3 times doesn't work because it has the same system time and so generates 3 times the same number. What's the best way to let it generate 3 random numbers (they may be the same)?

[Bazzy]

time(0) '0' means current time
warning C4244: that shouldn't create problems

Same numbers: You should call srand(time(0)) only once in your program. Move it outside the function, a good place is at the beginning of main

[Bv202]

Hi Bazzy

Thank you very much - I understand how it works now =)

[Hammurabi]

Bazzy spoke too quickly here. The 0 in time(0) is actually a null pointer. time() will write its result to the given address as well as return it if this pointer is non-null.

[helios]

Bazzy spoke too quickly here. The 0 in time(0) is actually a null pointer.

Did he say otherwise?

[Hammurabi]

Yes. He said

'0' means current time

This is wrong since it always gives the current time, whether or not the pointer is null.