The code this far has the numbers being put in a linked list. How can I do something like this:
Would you like to enter an integer (y for yes/n for no)? y
Enter an integer:100
Would you like to enter an integer (y for yes/n for no)? y
Enter an integer:30
Would you like to enter an integer (y for yes/n for no)? y
Enter an integer:50
Would you like to enter an integer (y for yes/n for no)? y
Enter an integer:10
Would you like to enter an integer (y for yes/n for no)? n
Your list in reverse order is:
10 30 50 100
Here is the code. Do I need to make another funciton?
thank you, please help.
#include<stdio.h>
#include<stdlib.h>
/* Link list node */
struct node
{
int data;
struct node* next;
};
/* Function to reverse the linked list */
staticvoid reverse(struct node** head_ref)
{
struct node* prev = NULL;
struct node* current = *head_ref;
struct node* next;
while (current != NULL)
{
next = current->next;
current->next = prev;
prev = current;
current = next;
}
*head_ref = prev;
}
/* Function to push a node */
void push(struct node** head_ref, int new_data)
{
/* allocate node */
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
/* put in the data */
new_node->data = new_data;
/* link the old list off the new node */
new_node->next = (*head_ref);
/* move the head to point to the new node */
(*head_ref) = new_node;
}
/* Function to print linked list */
void printList(struct node *head)
{
struct node *temp = head;
while(temp != NULL)
{
printf("%d ", temp->data);
temp = temp->next;
}
}
/* Drier program to test above function*/
int main()
{
/* Start with the empty list */
struct node* head = NULL;
push(&head, 20);
push(&head, 4);
push(&head, 15);
push(&head, 85);
printList(head);
reverse(&head);
printf("\n Reversed Linked list \n");
printList(head);
getchar();
}