Console output of unsigned chars (initialized by hex) gives cyrillic output

[Vetal]

Hi,

please, help to understand.

PROBLEM:I make the output with cout of unsigned chars, that are initialized as hex and receive ciryllic symbols on output with cout.
As I understand 0x63 is hex ASCII code of char 'c'; But I see cyrillic symbol 'я' instead... I don`t understand why!!!


CODE:

unsigned char Ar[2]={0x63,0x63};
cout << Ar[0]<<' '<< Ar[1]<< endl;


OUTPUT:
я я

SHOULD BE: c c

[vlad from moscow]

Now insert your code snip in the simple program and test it

#include <iostream>

int main()
{
   unsigned char Ar[2]={0x63,0x63};
   std::cout << Ar[0]<<' '<< Ar[1]<< std::endl;
}

For example you can test the code online at www.ideone.com

[Vetal]

It works....
I will try on my compiler and will post the result here...

[vlad from moscow]

It looks like the problem is in somewhere else. The code snip you showed is irrelevant.

[Vetal]

And what about this...(((


#include <iostream>
int main()
{
unsigned char Ar[2] ={0x7c,0xf2};
std::cout << Ar[0]<<' '<< Ar[1]<< std::endl;
}

OUTPUT: | �

What is a problem here...

[Cubbi]

Looks correct to me, 0x7c is the ascii code of |, and 0xf2 is invalid, which is correctly rendered as the replacement character �

[Vetal]

0xf2 is ASCII code of '/'

[Chervil]

I think you mean 0x2f is the ASCII code of '/'.

[Vetal]

Thank You, Guys,

I thought, that hex will be outputted as chars latin symbols...from A-to z...
I looked through the ASCII table and understood my mistake.... that number of symbols in ASCII table are more than the number of only alphabetical chars)))

Thank You!