C++ problems

[dn54321]

I have a problem, When i run my Program, it tells me to input a name which is what is't meant to do, but when it says are you sure it's (name), it only shows the first letter

using namespace std;
int main ()
{
	char yeh, yes, ya, yep;
	char yess;
	char Name;
	char Answer;
    yess == yeh, yes, ya, yep;
cout << "What is your name?\n";
cin >> Name;
cout << "Are you sure it is " << Name << "?";
cin >> Answer;
if (cin >> yess)
	cout << "\nGood!";
else
cout << "\nSo,";
system("PAUSE");
return 0;
}

[ar2007]

there are several problems:
0) variables must be declared with the first letter lowercase letter;

1) line 8 does not fit as you declared values ​​'yess', but also because I believe that in order to do what you want, 'yess' must be of type string;

2) line 13, if I understand what you wanted to do, you should write:
if (answer == yess) ...

but precisely, what did you do?

[ypfz3TCk]

I think you should use std::string rather than char.
eg

string name;
cout << "What is your name?";
cin >> name;
cout << "Are you sure it is " << name << "?" << std::endl;

You are using type char as the variable which for your program will store 1 character only. If you want to get input of a name - a string of characters combined - you need to use a string type as the storage variable.
hth

[mutexe]

0) variables must be declared with the first letter lowercase letter;

Nonsense.

[ar2007]

0) variables must be declared with the first letter lowercase letter;


Nonsense.

more precise:
is a convention.

[gobiking]

he will have an issue if he types in a first and last name so:
getline(cin,"name of your string")
will get whatever you type in for that line of strings

otherwise if he types in Mr. Anderson it will only output Mr.