Array access via * and []

[Nubcake95]

I don't think there is a diffence accessing an array element (Correct me if I'm wrong!) with * or [n]? Is it just a choice of preference?

  char string[] = "This is a string";

  //First element 
  std::cout << *string << std::endl;

  //Same 
  std::cout << string[0] << std:: endl;

Thanks

[Zhuge]

They are equivalent, but most people will use [] for arrays because it makes it immediately clear you are accessing an array instead of possibly just dereferencing a normal pointer.

[jidder]

I think this page might be helpful :)
http://www.learncpp.com/cpp-tutorial/68-pointers-arrays-and-pointer-arithmetic/

[Nubcake95]

Thanks for clearing that up & the link .

[MiiNiPaa]

In this case it works the same, but there is many other cases where behavior of there operations is completely different.
It is important to save semantic: Do you dereferencing pointer to char which points to desired letter, or you are selecting array element?
Choosing right operator will improve readability and can save you frome some errors.
Example

char* x = find(someCString, 'a');
std::cout << *x << std::endl; //dereferencing pointer to found character

char* y = newString(oldString);
std::cout << y[0] << std::endl; //Choosing first character of some c-string