Passing char* argv[] from main

[pata]

How would I pass a char pointer to a array of pointers to a function? (think i said that right) I want to print out the strings from the command line arguments but this prints only the first char. seems like im dealing with a multidimensional array... im confused..

  #include <iostream>


using namespace std;

void cstring(char *x[], int z);



int main(int argCnt, char * charArray[])
{

cstring(charArray,argCnt);


}

void cstring(char *x[],int z){
    for(int i = 0;i != z; ++i)
        cout << *x[i] << endl;
}

[Rechard3]

hi.
there seems to be one flaw from the outside:
in line 20, the expression you're using is a three level pointer.
your writing is the same as:

cout<<***(x+i)<<endl;

that should explain it.


try using

cout<<x[i]<<endl;

[MiiNiPaa]

void cstring(char *x[],int z){
    for(int i = 0;i != z; ++i)
        cout << x[i] << endl;
}

[pata]

thanks! i got it however if its a pointer, why doesnt it need to be dereferenced?


cout<<***(x+i)<<endl;
this gave error:
|20|error: invalid type argument of unary '*' (have 'char')|

[MiiNiPaa]

its type is char**
when we use subscript operator x[i] we gor char*, which is c-string. And << operator have overload which supports x-strings.
Compare:

const char* a = "Hello";
std::cout << a;

const char* b[] = {"hello", "world", "!"};
for (int i = 0; i < 3; +++i)
    std::cout << b[i] << std::endl;