delete all occurrences of x from a linked list

[Eyad]

Given a number x, write a program to delete all occurrences of x from a linked list
in one iteration. That is, you can not scan the list more than once.

It only deletes the first occurrence of X, can someone help fixing it please?

void DelAcc(Node*& head, int X)
{
	if((!head)||(!head->next && head->value!=X))
	{
		cout<<"could not find "<<X<<" in the list\n";
		return;
	}
	if(!head->next && head->value==X) {delete head; head=NULL; return;}
	Node* tmp = head;
	Node* t;
	while(tmp->next)
	{
		if(tmp->next->value == X)
		{
			t = tmp->next;
			tmp->next = tmp->next->next;
			delete t;
			return;
		}
		tmp=tmp->next;
	}
	cout<<"could not find "<<X<<" in the list\n";
}

[hanst99]

if(tmp->next->value == X)
		{
			t = tmp->next;
			tmp->next = tmp->next->next;
			delete t;
			return;
		}

{delete head; head=NULL; return;}

Questions?

[Eyad]

covering probability!

[Eyad]

COME ON GUYZ!!!

[Tesla]

Are you sure that the function isn't working? This will say
"Could not find << X << in the list"
every time because the cout statement is below the loops. Just a suggestion. :)

[Athar]

So again, what do you think the return in line 18 does? Especially in regard to your question?

[Eyad]

i removed it and i ran the code, but still it only deletes the first occurrence of X

[Athar]

If the occurrences are adjacent, that is because you're skipping two elements when erasing one. You forgot an else.

[Eyad]

thx for trying to help. but i do not get it. anyways i'll try to figure it out myself.