How to deduce a native array in a template function?

[JUANDENT]

Hi,

I used to know this but I think I am just exhausted. I want something like this:

	template<int N, int array[N]>
	static bool anyNonZero( int (array&)[N])
	{
		for( int i=0; i < N; ++i)
		{
			if (array[i] != 0)
				return true;
		}
		return false;
	}

in order to call it like so:

int count[2];
if(anyNonZero(count))
{ /////
}

but I get compilation errors!
Please help!

[JLBorges]

template < typename T, std::size_t N > using native_array_type = T[N] ;

template < typename T, std::size_t N >
constexpr bool any( const native_array_type<T,N>& arr, const T& value = T{} )
{
    for( const T& v : arr ) if( v == value ) return true ;
    return false ;
}

int main()
{
    constexpr const int a[] { 12, 0, 23, 5, 9 } ;
    constexpr bool found_zero = any(a) ;
}

[coder777]

	template<int N, typename array> //[EDIT] not type required
	static bool anyNonZero( int (&array)[N])
	{
		for( int i=0; i < N; ++i)
		{
			if (array[i] != 0)
				return true;
		}
		return false;
	}

[seeplus]

template<size_t N>
static bool anyNonZero(const int (&array)[N])
{
	return std::any_of(std::begin(array), std::end(array), [](int i) {return i != 0; });
}

[JUANDENT]

Thanks!!!!