Initializing a struct to zeroes

[Hammurabi]

I know you can initialize an array to all zeroes like so:

int a[10] = { 0 };

And, as another example, this would initialize the first element to 1 and the rest to zero:

int a[10] = { 1 };

But can you do the same thing with a struct?

struct Thing {
    int a, b, c;
};

Thing thing1 = { 0 };  // all members 0
Thing thing2 = { 1 };  // Member a = 1, b = c = 0 

I've tested it and it seems to work, but is it guaranteed to work by the standard? (I'm trying to read that thing, but OUCH, what a document! It hurts my head.)

[Bazzy]

Don't use that initialization style on C++, use a constructor:

struct Thing {
    int a, b, c;
    Thing ( int A=0, int B=0, int C=0 ) : a(A), b(B), c(C){}
};

Thing thing1;//a=b=c=0
Thing thing2 ( 1 );//a=1 b=c=0 

[Hammurabi]

I was asking what the standard says about this exact situation:

struct Thing {
    int a, b, c;
};

Thing thing1 = { 0 };  // all members 0
Thing thing2 = { 1 };  // Member a = 1, b = c = 0 

Is it guaranteed to work as indicated in the comments?

[jsmith]

No, it can't.

Consider if the struct contained an int and a std::vector().

[Hammurabi]

It seems to work.

#include <iostream>
#include <vector>

struct Thing {
    int a, b, c;
    std::vector<int> v;
};

int main() {
    Thing x = { 1, 2, 3 };
    std::cout << x.a << x.b << x.c << '\n';
    std::cout << x.v.size() << '\n';
    x.v.push_back( 456 );
    std::cout << x.v[0] << '\n';
}