Masking the password

[Default]

Hi! I am making a program that keeps things like passwords. I wanna make a password to access this program. But i have a question:
how change password letters into '*'
thanks for help!

[jsmith]

You must turn off character echoing when you read the user's input and, for each character input, you'll need to output an "*" instead. Of course then you need to handle specially the backspace key, left/right arrows, home/end, etc.

The actual implementation depends on your OS. For DOS getch() or getche() (I can't remember which) does the trick. For Un*x you have to turn off terminal echoing on stdin via termios settings.

[ponki d monkey]

You can use something like character=getch();. It will get the value of the character that you type, but it will not display it. Then you can just use conditional statements to display an "*". And as mentioned above, you need to set the backspace key, left/right arrows, home/end, etc. manually...

[Default]

Thanks!
(I made it :-))

[CheesyBeefy]

Sorry, I'm having the same problem, but I don't understand your answer. (I'm fairly new to C++)

My program takes your created password and saves it to a text document, but I don't want the password to be seen while it is being typed in. (*'s to replace characters.)

Could you please provide an example? I am using Windows with VC++ 2008 Express Edition.

Thanks in advance,
CheesyBeefy

[jsmith]

If you read the user's input with getch(), the characters entered are not automatically echoed to the screen. So if you use this function, then any time the user enters a character, you can cout << '*' << flush to print an asterisk instead.

However, you will have to write special code to handle keypresses such as Backspace, home/end, left/right arrows, and enter.