About my Task

[oguzuslu]

Hello guys,
I have to write this program but i don't understand to the problem. Please show me the way or can you write a seample?

Thanks.

Problem is ;

Write a program to deterrmine the coefficient A,B,C of the equation Ax+By+C=0 of a straight line that pass through 2 given points in a plane.

[Drue]

I made one for my algebra class. Here.

#include <cstdio>
#include <cstdlib>
#include <iostream>





using namespace std;



int  main(int nNumberofArgs, char* pszArgs[])
{

  
 cout << "Thank you for using my product.";

    int directOrLinear;

    system("title Linear Answers----Drue Peters");
system("cls");
cout  << "        .................................................................\n"
      << "        .                                                               .\n"
      << "        .                                                               .\n"
      << "        .                         REMEMBER!!!!!                         .\n"
      << "        .                If solving for perpindicular line              .\n"
      << "        .                slope must be opposite reciprocral             .\n"
      << "        .                                                               .\n"
      << "        .                        Decimals Only!                        .\n"
      << "        .                           Convert                            .\n"
      << "        .                                                               .\n"
      << "        .................................................................\n"

      << "               If you want to solve a Linear Equation                 press  1.\n"
      << "               If you want to solve a Direct Variation                press  2.\n"
      << "               If you want to solve for the slope                     press  3.\n";


      cin >> directOrLinear;

      switch(directOrLinear)
      {
        case 1:
        // Y=MX+B
        int lOption;
        system("title Solve for Linear Equation");
        system("cls");
        cout << "If you have one coordinate Press  1.\n";
        cout << "If you have two coordinates Press 2.\n";
        cin  >> lOption;
        switch(lOption)
        {
        case 1:
        long double linearX;
        system("cls");
        cout << "Enter in the X coordinate.\n";
        cin  >> linearX;
        system("cls");

        long double lX;
        lX= (linearX) + 0;

        cout << "X = " << lX;
        long double linearY;
        cout << "\nEnter in the Y coordinate.\n";
        cin  >> linearY;
        system("cls");
        cout << "Your coordinates are (" << lX << "," << linearY << ")";

        long double lslope;
        system("cls");
        cout << "Enter in the slope of the line.\n";
        cin  >> lslope;
        system("cls");
        cout << "Your coordinates and slope are (" << lX << "," << linearY << ") m = " << lslope;
        system("pause>nul");

        long double linearProduct;
        linearProduct = lX * lslope;



        long double linearAnswer;
        linearAnswer = linearY - linearProduct;

        long double lFinalAnswer;
        system("title Linear Equation");
        system("cls");
        cout << "Your equation equals...\n\n"
             << "Y= " << lslope << "x + " << linearAnswer << "\n";
        system("pause>nul");
        return 1;




        case 2:
        system("cls");
        long double lX2;
        system("title Slope");
        system("cls");
        cout << "Enter in the X coordinate.\n";
        cin >> lX2;

        long double lY;
        system("cls");
        cout << "Enter in the Y coordinate.\n";
        cin >> lY;

        long double lX3;
        system("cls");
        cout << "Enter in the second X coordinate.\n";
        cin >> lX3;

        long double lY2;
        system("cls");
        cout << "Enter in the second Y coordinate.\n";
        cin >> lY2;



        long double slope;
        slope = (lY-lY2)/(lX2-lX3);




      system("cls");
        cout << "Your coordinates and slope are...\n";
        system("pause>nul");
        cout << "(" << lX2  << "," << lY  << ")\n"
             << "(" << lX2 << "," << lY2 << ")\n"
             << "M = " << slope;
        system("pause>nul");



        long double lProduct;
        lProduct = lX2 * slope;



        long double lAnswer;
        lAnswer = lY - lProduct;


        system("title Linear Equation");
        system("cls");
        cout << "Your equation equals...\n\n"
             << "Y= " << slope << "x + " << lAnswer << "\n";
        system("pause>nul");



             }




















        case 2:
        int dvOption;
        system("cls");
        system("title Solve for Direct Variation");
        cout << "If you're finding Y when X = ... Press 1.\n"
             << "If you're finding X when Y = ... Press 2.\n\n";
        cin  >> dvOption;

        switch(dvOption)
       {
        case 1:
        long double dvX1;
        system("cls");
        system("title For Y");
        cout << "Enter the X coordinate. \n";
        cin  >> dvX1;


        long double dvY1;
        system("cls");
        cout <<  "X = " << dvX1;
        cout << "\n\nEnter the Y coordinate.\n";
        cin  >> dvY1;

        long double dvK1;
        dvK1 = (dvY1) / (dvX1);

        system("cls");
        system("title DV Values");
        cout << "Y = " << dvK1 << "x";

        system("pause>nul");

        long double dvX2;
        system("cls");
        cout << "Enter in the second X value.";
        cin  >> dvX2;

        long double dvFinalAnswer;
        dvFinalAnswer = dvK1 * dvX2;

        system("title Final Answer");
        system("cls");
        cout << "Y = " << dvFinalAnswer << ", when X = " << dvX2;
        system("pause>nul");




        case 2:
        system("cls");
        system("title For X");



        long double dv2X;
        system("cls");
        cout << "Enter the X coordinate. \n";
        cin  >> dv2X;


        long double dv2Y;
        system("cls");
        cout <<  "X = " << dv2X;
        cout << "\n\nEnter the Y coordinate.\n";
        cin  >> dv2Y;

        long double dv2K;
        dv2K = (dv2Y) / (dv2X);

        system("cls");
        system("title DV Values");
        cout << "Y = " << dv2K << "x";

        system("pause>nul");

        long double dv2Y2;
        system("cls");
        cout << "Enter in the second Y value.";
        cin  >> dv2Y2;

        long double dv2FinalAnswer;
        dv2FinalAnswer = dv2Y2 / dv2K;

        system("title Final Answer");
        system("cls");
        cout << "X = " << dv2FinalAnswer << ", when Y = " << dv2Y2;
        system("pause>nul");

       }

        case 3:
        long double mX;
        system("title Slope");
        system("cls");
        cout << "Enter in the X coordinate.\n";
        cin >> mX;

        long double mY;
        system("cls");
        cout << "Enter in the Y coordinate.\n";
        cin >> mY;

        long double mX2;
        system("cls");
        cout << "Enter in the second X coordinate.\n";
        cin >> mX2;

        long double mY2;
        system("cls");
        cout << "Enter in the second Y coordinate.\n";
        cin >> mY2;

        system("cls");
        cout << "Your coordinates are...\n";
        system("pause>nul");
        cout << "(" << mX  << "," << mY  << ")\n"
             << "(" << mX2 << "," << mY2 << ")\n";
        system("pause>nul");

        long double finalAnswer;
        finalAnswer = (mY2-mY)/(mX2-mX);




        system("cls");

        cout << "If M = nan, then slope is 0.\n\n"
             << "    Your slope is...\n"
             << "       M = " << finalAnswer;


             system("pause>nul");





default:
system("cls");
cout << "                " <<  directOrLinear << " is not a valid entry.";

      }






}

[Drue]

I've also made some of distance and midpoint a coordinate plane, and one for quadratic equations.

[oguzuslu]

thanks a lot.