How to get rid "+" word in loop

[siabapet]

How to get rid "+" on output
example:
i input: 6, the output is: 1 + 2 + 3 + 4 + 5 + 6 + = 21
but i want + after six is deleted

#include <iostream>
using namespace std;

int main()
{
    int n, sum = 0;
    cout << "Input = ";
    cin >> n;
    for (int i = 1; i <= n; ++i) {
        sum += i;
        cout << i << " + ";
    }
    cout << " = " << sum;
    return 0;
}

[markyrocks]

	int n, sum = 0;
	cout << "Input = ";
	cin >> n;
		for (int i = 1; i < n+1; ++i) {
			sum += i;
			if (i != n) {
			cout << i << " + ";
			}
			else { cout << i; }
			
		}
	cout << " = " << sum;
	return 0;

[JLBorges]

This is another way (print the last number in the end, outside the loop):

#include <iostream>

int main()
{
    int n ;
    std::cin >> n ;

    int sum = n ;

    for( int i = 1 ; i < n ; ++i )
    {
        sum += i ;
        std::cout << i << " + " ;
    }

    std::cout << n << " == " << sum << '\n'
              << n << " * " << n+1 << " / 2  == " << n * (n+1) / 2 << '\n' ;
}

[lastchance]

#include <iostream>
using namespace std;

int main()
{
    int n, i = 1;
    cout << "Input n: ";   cin >> n;
    for ( cout << i; i < n; cout << " + " << (++i) );
    cout << " = " << ( n * n + n ) / 2;
}

[siabapet]

thank you everyone i appreciate it

[seeplus]

#include <iostream>
using namespace std;

int main()
{
	int n {}, sum {1};

	cout << "Input = ";
	cin >> n;

	cout << 1;
	for (int i = 2; i <= n; sum += i++)
		cout << " + " << i;

	cout << " = " << sum;
	return 0;
}