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How to append output to prev. output?

QWERTYman (461)
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#include<iostream>
#include<fstream>
#include<limits>
using namespace std;

int main()
{
 string s, t, u, b;
 bool a = true;
 cout << "Welcome to the Address Book! "; 
 ofstream streamone("Address Book.txt");
 do
 {
 cout << "Enter a person's first and last name. ";
 cin >> s >> t;
 cout << "Input their full address. ";
 getline (cin, u);
 getline (cin, u);
 cout << "Enter their phone number: ";
 cin >> b;
 streamone << s << " " << t << endl;
 streamone << u << endl;
 streamone << b << endl << endl;
 streamone.close();
}
 while(a);
 streamone.close();
 cin.ignore( std::numeric_limits<std::streamsize>::max(), '\n' ); 
 cout << "Press Enter to exit this program...\n"; 
 cin.ignore( std::numeric_limits<std::streamsize>::max(), '\n' ); 
}

This is how the code stands, question answered.
Last edited on
Duthomhas (13206)
You accidentally wrote [\code] instead of [/code].

To append to a file, open it with the ios_base::app flag. Line 27 should read

ofstream streamone( "Address Book.txt", ios::app );

BTW, I recommend that you don't use >> to input strings. Use getline() instead.

Hope this helps.
QWERTYman (461)
Tried getline before, but it bugged. :(
I'll try ios::app, though.
[edit]I had to put getline twice in a row. LOL[/edit]
Last edited on
Duthomhas (13206)
1. Question: why do you keep opening and closing the file? Open it once, before the loop, and close it after the loop.

2. getline() fails if you mix it inappropriately with >>. You must be careful:
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#include <iostream>
#include <limits>
#include <string>
using namespace std;

int throw_off_bridge()
  {
  cout << "Auuuuuuuugh!\n";
  return 1;
  }

int main()
  {
  string name, color;
  int age;

  cout << "Halt!\nWhat is your name? ";
  getline( cin, name );

  cout << "What is your age? ";  // yes, but 'quest' takes a string...
  cin >> age;
  if (cin.get() != '\n')        // get rid of that pesky newline
    return throw_off_bridge();  // (unless the user didn't input a proper number)

  cout << "What is your favorite color? ";
  getline( cin, color );
  if (color != "yellow")
    return throw_off_bridge();

  cout << "Right. Off you go.\n";
  return 0;
  }


Hope this helps.

PS. Please edit that [\code] tag in your first post.
QWERTYman (461)
Another Q.
Is there a way to make a search option in there? (This is partly for my parents' benefit, and dear ol' Dad wants a search option.) I read about find_first_of, but I'm not sure where to put it/ how to do it. Any ideas(again)?
Duthomhas (13206)
Nice. Just one thing: the extra getline on line 17 just reads the newline left over from line 15. Check out what I did on lines 22 and 23.

BTW, your variable names stink. Please choose something that describes things better.

The way you output the file, it is formatted thus:
Harry Potter
4 Privot Lane
5551234
Ronald Weasly
The Burrow
5552345
Hermione Granger

5553456

This makes it very easy to search, since all you need to do is read it three lines at a time and compare.

For example, to search for a telephone number:
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struct person_t
  {
  string given_name, surname;
  string address;
  unsigned phone_number;  // notice that I changed this to a number

  person_t(): given_name(""), surname(""), address(""), phone_number(0) { }
  };

istream& operator >> ( istream& ins, person_t& person )
  {
  ins >> person.given_name
      >> person.surname;
  ins.get();

  getline( ins, address );

  string phone_number;
  getline( ins, phone_number );
  person.phone_number = 0;
  stringstream( phone_number ) >> person.phone_number;

  return ins;
  };

person_t find_phone_number( fstream& file, unsigned phone_number )
  {
  // make sure the file is reset
  file.clear();
  file.seekg( 0 );
  person_t person;

  // find the desired person
  while (file >> person)
    if (person.phone_number == phone_number)
      return person;

  // if not found, return nobody
  return person_t();
  };


You can do the same sort of thing for other members of the struct.

Hope this helps.
Last edited on
QWERTYman (461)
Most codes I write don't really need fancy names, but then...

Should I write that to a separate program that searches, or let the user decide between new/load and search, or...what?

Here is my current code:
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#include<iostream>
#include<fstream>
#include<limits>
using namespace std;

int main()
{
 string c, s, t, u, b;
 bool a = true;
 char d;
 system("TITLE Address Book Maker");
 for(int i = 0; i < 1; i++)
 {
 cout << "Welcome to the Address Book Maker!\nRules and Help Regarding Filenames\n 1. When naming a file you MUST put \".txt\" at the end.\n 2. To load a previous address book, type the EXACT name and put \".txt\" at the\nend(unless already there).\n"; 
 cout << "Ok! Now, hit ENTER to start.";
 cin.ignore( std::numeric_limits<std::streamsize>::max(), '\n' );
 system("cls");
 cout << "What will you call your Address Book file/What Address Book will you load?\n";
 cin >> c;
  cout << "Excellent! ";
 do
 {
 cout << "Now, enter a person's first and last name. ";
 cin >> s >> t;
 cout << "Input their full address (ex. 123 Road Rd. Boston, MA (insert zip code here)). ";
 getline (cin, u);
 getline (cin, u);
 cout << "Enter their phone number: ";
 cin >> b;
 ofstream streamone(c.c_str(), ios::app);
 streamone << s << " " << t << "'s address is" << endl;
 streamone << u << " and his phone number is" << endl;
 streamone << b  << "." << endl << endl;
 cout << "The program will show this:\n" << s << " " << t << "'s address is" << endl << u << " and his phone number is" << endl << b  << "." << endl << endl;
 do{
 cout << "Restart? (y or n) "; 
 cin >> d;  
   if(d == 'y' || d == 'Y')
     continue;
   else if(d == 'n' || d == 'N')
     a = false;     
 }while (d != 'y' && d != 'Y' && d != 'n' && d != 'N');
 streamone.close();
}while(a);
}
 return 0;
}
note: I like the way I did the getline, so nyeh. This isn't commercial(yet).
Last edited on
Duthomhas (13206)
If by "fancy names" you mean "descriptive, meaningful names" then it is your own fire for the roast. X-|

As for the design, it is up to you. It depends on who your target consumer is.

Good luck!
QWERTYman (461)
lol, I just started this crud.

This is as advanced as I've gone, and I'm afraid I'll screw up so badly, that I can't think of a way out of that. D:

Where is a good place to put this on the Internet?
Also, I want to concatenate the search engine to the Address Book Maker using an if-else statement. Where should it go?
Last edited on
Duthomhas (13206)
Heh heh, messing up is part of the learning process. Just keep regular backups and you can always undo a disaster. ;-)

Your ISP might provide some webspace, either for free or for a premium. You can buy space. You can use free file hosting services like MediaFire.

The main() function of a program is to direct the operation of the rest of the program. Anything that actually does stuff belongs in a subroutine.

For illustrative purposes:
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#include <algorithm>
#include <cctype>
#include <iomanip>
#include <iostream>
#include <string>
#include <vector>
using namespace std;

typedef vector <string> name_list;

void show_menu()
  {
  cout << "\nWhat would you like to do?\n\n"

       << "add names\n"
       << "delete a name\n"
       << "list names\n"
       << "quit\n\n"

       << "> ";
  }

string read_name()
  {
  string name;
  if (getline( cin, name ) and !name.empty())
    {
    string s = name;

    // make sure the name is in "given-name(s) surname(s)" order.
    int i = name.find( ',' );
    if (i != string::npos())
      {
      s = name.substr( i +1 ) +' ' +name.substr( 0, i );
      }
    }

  // get rid of extra spaces
  stringstream ss( s );
  string piece;
  name.clear();
  while (ss >> piece)
    {
    if (!name.empty()) name += ' ';
    name += piece;
    }

  return name;
  }

void add_names( name_list& result )
  {
  string name;

  cout << "\nPlease enter your friends names, one per line.\n"
       << "Press ENTER twice to finish.\n";

  while (true)
    {
    // get a name
    name = read_name();
    if (name.empty()) break;

    // add it to the end of our list
    result.push_back( name );
    }

  // Keep it sorted
  sort( result.begin(), result.end() );
  }

void delete_name( name_list& names )
  {
  cout << "\nEnter the name of the friend you wish delete\n"
       << "or just press ENTER to abort.\n\n"

       << "> ";

  string name = read_name();

  name_list::iterator i = find( names.begin(), names.end(), name );
  if (i != names.end())
    {
    names.erase( i );
    }
  }

void list_names( name_list& names )
  {
  cout << "\nYour friends are:\n";

  for (unsigned n = 0; n < names.size(); n++)
    cout << setw( 2 ) << right << n << ": " << names[ n ] << endl;
  }

int main()
  {
  string    user_input;
  name_list names;
  bool      done = false;

  cout << "Welcome to the friend counter.\n"

  show_menu();
  while (!done and getline( cin, user_input ))
    {
    switch (toupper( user_input[ 0 ] ))
      {
      case 'A': add_names( names ); break;
      case 'D': delete_name( names ); break;
      case 'L': list_names( names ); break;
      case 'Q': done = true; break;
      default:
        cout << "What? Try again> ";
      }
    }

  cout << "Good bye.\n";

  return 0;
  }


Well, that's all I want to type. Hope this helps.
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