please...me/Im a beginner

[hsh]

how can i calculate
(1/25)+(3/24)+(5/23)+(7/22)+(9/21)+(11/20)
using two (for loop)
the answer is=1.6791

[qudongfang]

try this:

double s = 0;
for(int i = 0;i <= 5;i++)
{
     s += (1 + 2 * i) / (25 - i);
}

[jsmith]

Above will not work unless you want zero. You'll need to do
this in the floating point domain. But I don't know why you'd
need two loops.

[hsh]

hi,it looks correct,but it doesn't work;
could you try it?
thanks very much...

[Maimaje Bello Abdullahi]

#include<iostream>
using namespace std;

int main()
{
	float a=1, b=25, total=0, sum=0;
	int count=0;

	while(count <= 5)
	{
		for(int i=0; i<5; i++)
		{
			for(int j=i; j<1; j++)
			{
				sum = a/b;
				cout<<a<<"/"<<b<<" = "<<sum<<endl;
				total = total + sum;
				a+=2;
				b--;
			}
		}
		count++;
	}
	cout<<"\nThe Total is"<<" = "<<total<<endl<<endl;
	return 0;
}

Hope this will help you

[hsh]

as an aswer to jsmith:because my teacher has said...(laughing)
--------------------------------------------------------------------------------------
bello...
thank you very very very much...
it works nice and perfect...kissss kiss kisssss

[cnoeval]

Hope this will help you

It will help him cheat on his schoolwork. Too bad it won't help him actually learn anything.

[qudongfang]

I just want to tell you the aglorithm before.

double s = 0;
for(int i = 0;i <= 5;i++)
{
     s += (double)(1 + 2 * i) / (25 - i);
}