X+=Y Understanding

[Madeirey]

Slightly confused/stumped on the statements:

x+=y

and

x=+y

I know if I had, say, x++ or y++ that would mean whatever number x or y was it would be added by 1. Or if I had, say, x=y++ it would equal x=y - 1. Or also if I had x=++y it would equal x=y. But then again, I could have that all wrong too.

[AceDawg45]

+= is the same as using x = x + y.
So if I had:

int x;
x = x + y;

That would be the same as:

int x;
x += y;

It is just a quicker way of doing this, like the increment operator (++)

Source: http://www.cplusplus.com/doc/tutorial/operators/

[MrHutch]

The first is just the same as saying x = x + y.

int x = 5;
iny y = 3;

x += y;  // x is now 8 

In the second, the plus is meaningless. It's just the same as x = y.

In prefix operations (++x), the value is incremented and then returned.
In postfix operations (x++), the value is returned then incremented.

int x = 0;
int y = 5;

x = y++;   // x = 5, y = 6
x = ++y;   // x = 7, y = 7; 

[LB]

iHutch105 wrote:

In postfix operations (x++), the value is returned then incremented.

No, the value is copied, the original is incremented, and the copy is returned.

[Madeirey]

Ah! Thank y'all so much. That helped a lot.