Reversing a string

[Bv202]

string tekst;
	cout << "enter a string: ";
	getline(cin, tekst);
	int size = tekst.length();
	
	for (int i = 0; i < size /2; i++)
	{
		string tempvar1 = tekst.substr(i);
		string tempvar2 = tekst.substr(size - 1 - i);
		tekst.replace(i, i+1, tempvar2);
		tekst.replace(size - 1 -i, (size - 1 - i) + 1, tempvar1);
	}

	cout << tekst << endl;
	return 0;

That code doesn't work. It displays the inserted string for like 100 times now :S

What's wrong with this?
It should reverse a string

For example: "this is a test" should become "test a si siht"

[Bazzy]

You can do this in a single line: tekst = string ( tekst.rbegin(), tekst.rend() );

[Bv202]

Thank you Bazzy.

Can you explain that line? I mean, what are the rbegin() methods and why use the function string()?

EDIT:
Ok, I understand rbegin() and rend(), but what about that function string()?

[Bazzy]

string ( ) is the string constructor which creates a new string object ( http://www.cplusplus.com/reference/string/string/string/ )

rbegin and rend are reverse iterators, an iterator is an object which acts in a similar way to a pointer ( http://www.cplusplus.com/reference/std/iterator/reverse_iterator/ http://www.cplusplus.com/reference/string/string/rbegin/ )
string ( tekst.rbegin(), tekst.rend() ) creates a string from the beginning to the of the reversed 'tekst'

[Bv202]

Ok, thank you very much =)