Complex NumbersThe brackets segmenting the operator in the polar call does not change the result. The formula is j...
Complex NumbersJust a note to this, I am looking at the result in polar form using abs() and arg(). The abs is ret...
Complex NumbersI am sorry I guess I should have stated that I am using the built in <complex> class. [code] #incl...
Complex NumbersI have an application that works with complex number. It simply asks the user to input 3 numbers (m...
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