Upgrading my code to include pointersIf you want to use first variant -> use: [code]nums [1][1][/code] or [code]*(*(nums+1)+1)[/code] i...
Upgrading my code to include pointersHi, [code] int i,j; i=j=5; int **nums=new int* [i]; for (int k=0;k<j;k++) ...
concatinationShow all your constructors and operator=.
concatination[code] Str Str:: operator+(const Str & append) const { //let's think that your initial Str value...
concatination[code] Str Str:: operator+(const str & st1) const { int used1=used+st1.used; char* ch1=...
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