cout arrays

[Cjigsaw]

Is there a way to cout an array?

void displayPrice(double money[])
{
 for(int i = 0; i < 5; i++)//I am making the array 5 elements

    {

        //using this as an example for a similar problem
       //

    }

       cout<<monkey[i]<<endl;//something like this. Can that be done?
                            //to print everything the array
}

I know the syntax is not accurate and I'm missing some code.

[Ganado]

Yes, move line 13 to be inside the loop. Assuming the length of the array is at least 5.
And I assume you mean 'money' not 'monkey'.

[keskiverto]

Assuming the length of the array

In other words: the length of an array is not passed to a function unless you do it explicitly.

void displayPrice( double money[], int size )
{
  for ( int i = 0; i < size; i++ )

If you keep the hardcoded "5", then the function can be used only to print exactly 5 first values from array.

[Toddinator716]

yes this has been solved by ganado, you would in fact be displaying 5 array values held at positions 0-4 of money/monkey

[Cjigsaw]

lol, I meant money lol. I need to start doing that in the future. Would you mind showing me how to use the same loop but using a pointer?

[keskiverto]

What do you mean? The money is a pointer.

[Ganado]

When you pass in an array into a function, it already degrades into a pointer.

I really don't understand why schools force you to use this horrible notation, but:

monkey[i] is equivalent to *(monkey + i) in pointer notation.

[Duthomhas]

Heh heh heh:

void displayPrices( double money[], int size )
{
  if (!size) return;
  std::cout << "$" << money[0];
  for (int n = 1; n < size; n++)
    std::cout << ", $" << money[n];
  std::cout << "\n";
}

template <std::size_t N>
void displayPrices( double money[N] )
{
  displayPrices( money, (int)N );
}

:^}

[Cjigsaw]

I think I got it everyone. May not be the best looking piece of code, but its working. I hope I don't get a lot of point deductions. I really appreciate everyone's help. I would love to pick everyone's brain and learn more. If anyone is interested.

[jonnin]

may as well … ask what you want to know.

theres another pointer approach, and its a good intro to the concept of an iterator.

char a[] = "abcde";
char* ap = a;
while(*ap)
{
cout << *ap;
ap++;
}

you basically advance a temporary pointer through the data, one location at a time, rather than index a base pointer + offset (which is what[] notation does for you).

Range based for loops and many stl tools work off this base concept. I used a c-string because it has an easy stop condition, but you can do it on any array/vector.

[George P]

As I mentioned here ( http://www.cplusplus.com/forum/general/269246/#msg1158758 ):

When passing a regular array to a function it is recommended you also pass the array's size. The number of elements. Hard-coding that information limits the reusability of your function.

void printArray(int arr[], int arrSize) not void printArray(int arr[])

[Cjigsaw]

Thanks for the info everyone. I don't due a whole lot these days. Feel free to add me on snapchat or whatever. stay-strong365. Not a whole lot of adults to talk to lol.

[George P]

#include <iostream>

template <typename T, size_t SIZE>
std::ostream& operator<<(std::ostream& os, T (&arr)[SIZE]);

int main()
{
   int iarr[] { 1, 2, 3, 4, 5 };

   std::cout << iarr << '\n';

   double darr[] { 0.0, 0.1, 0.5, 5.3, -12.9 };

   std::cout << darr << '\n';
}

template <typename T, size_t SIZE>
std::ostream& operator<<(std::ostream& os, T(&arr)[SIZE])
{
   for (size_t index { }; index < SIZE; index++)
   {
      os << arr[index] << ' ';
   }
   return os;
}